PHP coding questions... How to...

[WreckRman2]

Does anyone know how to make PHP count? For example I need to come up with the following and I don't want to manually do it. I'm lazy...

I need it to count from 1-6000 as follows:


1,2,3,4,5,6,7,8,9,10,11,....5995,5996,5997,5998,5999,6000

Thanks in advance...

[Goldfinger]

for ( x=0;, x < 6001, x++ {

echo ($x);

}

[Mark Hensler]

for ($i=0; $i<6000; print (++$i));

[Goldfinger]

man my code was very rusty haha.

[Mark Hensler]

[WreckRman2]

Originally posted by Max Albert
for ($i=0; $i<6000; print (++$i));

Thanks guys, this counted from 1 to 6000 but how can I add a comma after each number? I tried to add a comma everywhere in that code but all it did was return a parse error.

[Goldfinger]

for ($i=0; $i<6000; print (++$i . ","));

[Mark Hensler]

don't print comma after 6,000:
for ($i=0; $i<6000; $i++, print ($i % 6000) ? "$i, " : $i);

[WreckRman2]

Damn, you guys are good! Thanks a million...

[Kier]

Only problem with your code there Max, is that it has to perform and if() and a modulus six thousand times... which isn't ideal for the server.

This code doesn't:

$numbers = array();
for ($i=1; $i<6001; $numbers[]=$i++);
print implode(',', $numbers); 

[Mark Hensler]

True. That was pretty bad on my part.

But, an array isn't so hot either, it takes memory. implode() adds a certain load to the server too.

for ($i=0; $i<5999; print (++$i . ', '));
print ('6000'); 

[Kier]

Hehe, this thread could go on for quite some time

[Goldfinger]

for ($i=0; $i<6000; print (++$i . ', '));
print ('6000'); 

it has to be $i<6000 because it wont count 6000 because that woudl be equal to it .

[Mark Hensler]

It won't loop when $i==6000, BUT it's using pre-increment so when $i==5999 it prints 6000. Notice I'm also starting with $i=0, but it prints 1.

[jeffct]

It's easier than that, for loop not needed:

echo implode(',', range(1, 6000)); 

It's about 75% faster than using the for loop I believe. Built in PHP functions are good